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There are 5 green 7 red balls. Two balls are selected one by one without replacement, then the probability that first is green and second is red is,

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78

58

913

35132

answer is D.

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Detailed Solution

It is given that 5 are green and 7 are red balls.
So, the total number of balls is 5+7 = 12.
The probability of green balls is

\frac{Number of green balls}{Total number of balls} .

P G = 512

The probability of red balls is

\frac{Number of red balls}{Total number of balls}

P R = 712

Therefore, according to the question, the required probability will be,

P G × P R = 512 × 712 = 35132

Hence, option 4 is correct.

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