There are 6 red balls, 5 yellow and 3 pink balls in an sum. Two balls are drawn at random. What Is the probability that none of the drawn balls is of red colour ?

$$\begin{gathered} \text{ Total number of balls in the um }=6+5+3=14 \\ \text{ Total possible outcomes }=\text{ Selection of }2\text{ bails out of }14\text{ balls }{=}^{14}{C}_2=\frac{14\times 13}{1\times 2}=91 \\ \text{ The drawn balls are not of red colour. } \\ \text{ Total favourable outcomes }=\text{ Selection of }2\text{ balls out of remaining }8\text{ balls } \\ {=}^8{C}_2=\frac{8\times 7}{1\times 2}=28 \\ \text{ Therefore, Required probability }=\frac{28}{91}=\frac{4}{13} \end{gathered}$$