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There are 7 identical white balls and 3 identical black balls. The number of distinct arrangements in a row of all balls, so that no two black balls are adjacent is

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120

42 × 5⁴

answer is C.

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Detailed Solution

7 white balls in a row → 1
3 black balls in 8 places = ⁸C₃
T.R.A= ⁸C₃= 56

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