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Q.

There are as many notes as number of oxygen atoms in 24.8 gm
$N a_{2} S_{2} O_{3} . 5 H_{2} O (M . w t . = 248)$ . A note counting machine counts 48 million notes per day. Number of days taken to count these notes is $10^{x}, x =______$

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answer is 16.

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Detailed Solution

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No. of “O” atoms

$= \frac{24.8}{248} \times N \times 8$

$= 0.8 \times 6.023 \times 10^{23}$

$1 d a y \to 48 \times 10^{6}$

$x \leftarrow 4.8 \times 10^{23}$

$x = \frac{4.8 \times 10^{23}}{4.8 \times 10^{7}}$

$= 1 \times 10^{16}$

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There are as many notes as number of oxygen atoms in 24.8 gmNa2S2O3.5 H2O(M .wt.=248). A note counting machine counts 48 million notes per day. Number of days taken to count these notes is 10x, x=______