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Q.

There are five balls at rest at equal distances in a straight line on a smooth horizontal surface. Their masses are in geometrical progression with common ratio 2 and their coefficients of restitution are each 2/3. If the first ball is started towards the second with velocity u, then the velocity communicated to 5th ball is  u(xy)(yx).  Find the value of x+y 

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answer is 14.

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Detailed Solution

We know that velocity of 2nd ball after collision is given by υ2=u1(1+e)m1(m1+m2)+u2(m2m1)(m1+m2)

 In present problem u2= 0, m2= 2m1 and e = 2/3,  hence υ2=u(1+23)(m1+2m1)=59u 

As four exactly similar type of collisions are taking place successively, 

hence velocity communicated to fifth ball υ5=(59)4u

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