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Q.

There are  'm' men and two women participating in a chess tournament each participant plays two games with every other participant if the number of games played by the men between themselves exceed the number of games played between the men and the women by 84, then the value of m 

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a

11

b

7

c

12

d

9

answer is A.

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Detailed Solution

(No of games played by m men among men)

-(No of games played by m men with 2 women) = 84

∴mC2 (2) -2(2×m)=84 ⇒m(m-1)-4m=84 ⇒m2-5m-84=0 ⇒(m-12) (m+7)=0 m=12

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