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There are two blocks shown in the figure, which are kept in contact with each other on a smooth surface. What is the force on the lighter block and its acceleration?

:

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6 N, 1 m / s^{2}

4 N, 1 m / s^{2}

10 N, 1 m / s^{2}

0 N, 0 m / s^{2}

answer is B.

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Detailed Solution

There are two blocks which are kept in contact with each other on a smooth surface. The force on the lighter block and its acceleration is

4 N, 1 m / s^{2}

.
Given:
Force

F = 10 N

Mass

M_{1} = 6 kg

Mass

M_{2} = 4 kg

To find:
Force on the lighter block and acceleration
Now, we calculate the total mass,

m = M_{1} + M_{2}

= 6 + 4

= 10 kg

Therefore the total acceleration

(a)

is given by

F = ma

\Rightarrow a = \frac{F}{m}

\Rightarrow a = \frac{10}{10}

\Rightarrow a = 1 m s^{- 2}

Now, Force on the lighter block

F = M_{2} a

\Rightarrow F = 4 \times 1

\Rightarrow F = 4 N

Therefore, the force on the lighter block is

4 N

and acceleration is

1 m / s^{2}

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