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Q.

There are two equipotential surface with same potential as shown in figure. The distance between them is r. The charge of –q coulomb is taken from the surface A to B, the resultant work done will be

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a

W = zero

b

$W = - \frac{1}{4 {πε}_{0}} \frac{q}{r^{2}}$

c

$W = \frac{1}{4 {πε}_{0}} \frac{q}{r^{2}}$

d

$W = \frac{1}{4 {πε}_{o}} \frac{q}{r}$

answer is D.

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Detailed Solution

The work done is given by $= q (V_{2} - V_{1}) = 0$

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There are two equipotential surface with same potential as shown in figure. The distance between them is r. The charge of –q coulomb is taken from the surface A to B, the resultant work done will be