There are two holes, each of cross-sectional area a, on the opposite sides of a wide rectangular tank containing a liquid of density $ρ$ . When the liquid flows out of the holes, the net force on the tank is [h is the vertical distance between the two holes.]

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$2 a ρ g h$

$4 a ρ g h$

$0.5 a ρ g h$

$ρ g h$

answer is A.

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Detailed Solution

Let H and H+h are the heights of upper and lower orifices from free surface of water

$F = F_{2} - F_{1} = ρ A ({v_{2}}^{2} - {v_{1}}^{2}) = ρ A (2 g (H + h) - 2 g H) = ρ A (2 h g)$

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