Q.

There are two identical small holes of area of cross section a on the opposite sides of a tank containing a liquid of density ρ . The difference in height between the holes is h. The tank is resting on a smooth horizontal surface. The horizontal force which will have to be applied on the tank to kept it in equilibrium is

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a

 2pagh 

b

 ghpa 

c

2ghρa

d

ρgha

answer is C.

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Detailed Solution

Let the holes be at a height of h1 and h2 and speed of liquid coming out be v1 and v2  

Thrust force, 

F=F1F2=ρav12ρav22

=ρa2gh1ρa2gh2

=2ρagh1h2=2ρagh

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