There are two identical small holes of area of cross section a on the opposite sides of a tank containing a liquid of density $ρ$ . The difference in height between the holes is h. The tank is resting on a smooth horizontal surface. The horizontal force which will have to be applied on the tank to kept it in equilibrium is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$ghpa$

$\frac{2 gh}{ρ a}$

$2pagh$

$\frac{ρ g h}{a}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Let the holes be at a height of h₁ and h₂ and speed of liquid coming out be v₁ and v₂

Thrust force,

$F = F_{1} - F_{2} = {ρav}_{1}^{2} - {ρav}_{2}^{2}$

$= ρa (2 {gh}_{1}) - ρa (2 {gh}_{2})$

$= 2 ρag (h_{1} - h_{2}) = 2 ρagh$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test