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There are two stones. One stone is thrown from a height in a direction parallel to the earth’s surface, while the other is dropped from the same height. Choose the correct statement.

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Stone-1 will reach the ground first

Stone-2 will reach the ground first

Both will reach the ground simultaneously

None of the above

answer is C.

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Detailed Solution

In the above case, both the stone will reach the ground simultaneously.
Let

h

be the height
Stone-1:
It is thrown parallel to the earth’s surface, so its initial velocity is zero

u = 0

a = g

s = h

Applying equation of motion:

s = ut + \frac{1}{2} a t^{2}

Putting all the values

h = 0 + \frac{1}{2} g t^{2}

\Rightarrow t = \sqrt{\frac{2 h}{g}}

Stone-2:
It is dropped from the height, so its initial velocity is zero
So,

u = 0

a = g

s = h

`
Applying equation of motion:

s = ut + \frac{1}{2} a t^{2}

Putting all the values

h = 0 + \frac{1}{2} g t^{2}

\Rightarrow t = \sqrt{\frac{2 h}{g}}

Hence, the time taken by both the stones to reach the ground is equal. So, both stones will reach the ground simultaneously.

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