There are two Vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier scale of one of the calipers $(C_{1})$ has 10 equal divisions that correspond to 9 main scale divisions. The venire scale of the other caliper $(C_{2})$ has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers $C_{1}$ and $C_{2}$ , respectively, are

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2.87 and 2.83

2.87 and 2.87

2.87 and 2.86

2.85 and 2.82

answer is C.

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Detailed Solution

$\begin{array}{l} F o r C_{1}, \\ L C = M S D - V S D = 1 m m - 0.9 m m = 0.1 m m = 0.01 c m \\ [∵ 10 V S D = 9 m m] \\ R e a d i n g = M S R + (L C \times n) = 2.8 + (0.01 \times 7) = 2.87 c m \\ F o r C_{2}, \\ L C = M S D - V S D = 1 m m - 1.1 m m = - 0.1 m m = - 0.01 c m \\ [∵ 10 V S D = 11 m m] \\ R e a d i n g = 2.8 + (10 - 7) \times 0.01 = 2.83 c m \end{array}$