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Q.

There exists a non-conducting disc of radius R and having a charge density of σ0. What will be the work done by the electrostatic repulsion when radius of the disc becomes 2R. Assume during expansion charge distribution remains uniform at all the time. If work done by electric force is of the form Aσ02R3B0 in simplest ratio. Then the value of (A+B) will be?

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answer is 4.

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Detailed Solution

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Self-energy of the disc is given by Uself2Q33π20R,Q=σ0.πR2

We=UiUf=2Q23π20[1R12R] Q23π20Rσ2π2R43π20Rσ2R330

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