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Q.

There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction as shown in the figure. The radius of curvature of path of particle at the highest point is
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a

None of the above.

b

\large \frac{{{q^2}{E^2}{u^2}}}{{{m^2}{g^2}}}

c

\large \frac{{{q^2}{E^2}{u^2}}}{{{m^2}{g^3}}}

d

\large \frac{{{q^2}{E^2}{u^2}}}{{mg}}

answer is D.

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Detailed Solution

At time t.
 

\large R = \frac{{{V^2}}}{{{a_n}}} = \frac{{{u^2}}}{{{{\cos }^2}\theta \times a\cos \theta }}


 

\large = \left( {\frac{{{u^2}}}{{\frac{{qE}}{m}{{\cos }^3}\theta }}} \right)


As θ=90o, R→∞

 

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