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Q.

There is a chain of length 6 m and coefficient of friction $0.5 .$ What will be the maximum length of chain which can be held outside of table without sliding (in meters)

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answer is 2.

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Detailed Solution

$μ = \frac{h a n g i n g p a r t}{R e m a i n i n g p a r t}$

$\frac{1}{2} = \frac{h a n g i n g p a r t}{r e m a i n i n g p a r t}$

hence the hanging part will be $\frac{1}{3} \times total length = 2 m$

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