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Q.

There is a current of 1 A passing through the cross - section of a conductor. The number of electrons passing through the cross - section in 1 second will be

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a

6.25×1025

b

6×1017

c

6.25×1018

d

6×1018

answer is B.

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Detailed Solution

I=qt=net1=nt.1.6×1019

nt=11.6×1019=6.25×1018

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