There is a point source of light at a depth 8m below the surface of water. An observer in air sees the image of the source. Line of sight of observer makes an angle ${53}^0$ with the normal to surface. (use : $\sqrt{7}=2.65,\mu =\text{of water\hspace{0.17em}}=4/3$ )

Percentage of power coming out of the water assuming no absorption of light by water and 100% refraction with in the circle of illuminance is 16.875%

Horizontal distance between object and its image is 3.38m

Apparent depth of image from surface is 2.53m

Radius of circle of illuminance is 9.05m