AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

There is a regular hexagon MNOPQR of each side 5 cm and symmetric about NQ. Suresh and Rushika divided it into different ways. Find the area of this hexagon using both ways.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

64 {cm}^{2}

63 {cm}^{2}

62 {cm}^{2}

60 {cm}^{2}

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given,
A hexagon = MNOPQR
Sides of hexagon = 5 cm
The area of hexagon = A
Question Image

1st Suresh’s Method
It is a regular hexagon,
The hexagon divides into two congruent trapeziums = NQ
We know

A = \frac{1}{2} \times

Sum of the parallel sides × distance between them [A=area of trapezium]

A = 4 \times \frac{11 + 5}{2}

A = 2 \times 16

A = 32 {cm}^{2}

Now, the area of hexagon

= 2

\times

area of trapezium

= 2 \times 32

= 64 {cm}^{2}

2nd Rushika’s method
In

△ MNO

And

△ RPQ

Both are congruent triangles with altitude = 3 cm
Now,

= \frac{1}{2} \times base \times height

[area of a triangle]
Area of

△ MNO

= \frac{1}{2} \times 8 \times 3

= 12 {cm}^{2}

Area of

△ RPQ

We know,
= length × breadth [area of a rectangle]

MOPR = 8 \times 5

= 40 {cm}^{2}

Again, area of hexagon

MNOPQR

= 40 + 12 + 12

= 64 {cm}^{2}

Hence, calculated area by both method and we obtain that the area of the given hexagon =

64 {cm}^{2}

Correct option is 1.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!