There is a small air bubble inside a glass sphere ( $μ$ = 1.5) of radius 10 cm. The bubble is 4 cm below the surface and is viewed normally from the outside. The apparent depth of the bubble is

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3 cm below the surface

5 cm below the surface

8 cm below the surface

10 cm below the surface

answer is A.

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Detailed Solution

$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R} \Rightarrow \frac{1}{v} - \frac{1.5}{- 4} = \frac{1 - 1.5}{- 10} \Rightarrow v = - 3.07 cm$

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