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There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between in the limits 589.0 V to 589.8 V. The potential at a point on the sphere whose radius vector makes an angle of 60° with the direction of the field is x. Find the value of 10x

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answer is 5892.

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Detailed Solution

Potential gradient is given by $ΔV = E.d= 0 .8$

So at centre the voltage is 589.4

The point which makes an angle of 60⁰ will be at a distance of $\frac{d}{2} \cos θ$ from centre.

$∆ V = E (d + \frac{d}{2}) = 0.6 V$

Hence ,maximum potential at a point on the sphere which makes 60⁰with field will be 589.2V

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