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There is an axially symmetric non uniform and constant magnetic field whose magnetic lines of forces are as shown. A ring of radius R is placed such that its axis coincides with axis of symmetry of magnetic field. At shown instant the constant velocity of ring is along its axis. The magnitude of magnetic field at periphery of ring is B and its component in plane of the ring is $B_{R} .$ Then the magnitude of induced emf in the ring at shown instant is

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$2 π R B_{R} v$

$2 π R B v$

$\frac{2 π R B_{R}^{2} v}{B}$

$\frac{2 π R (B^{2} - B_{R}^{2}) v}{B}$

answer is A.

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Detailed Solution

The flux in tube of magnetic lines of force remains same. Calculate the difference in flux from the periphery of ring.

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