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There is an electric field in +X-direction. If the work done in moving a charge of 0.2C through a distance of 2m along a line making an angle of $60^{0}$ with +X-axis is 4J. The value of E is

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$4 N C^{- 1}$

$20 N C^{- 1}$

$\sqrt{3} N C^{- 1}$

$5 N C^{- 1}$

answer is D.

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Detailed Solution

$W = F s \cos θ = q E \cos θ$

$4 = 0.2 E \cos 60^{0} 2 E = 20 N / C$

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