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There is an error of $\pm 0 . 04 cm$ in the measurement of the diameter of a sphere. When the radius is 10cm, the percentage error in the volume of the sphere is

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$± 12$

$± 1 . 0$

$± 10 . 8$

$± 0 . 6$

answer is D.

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Detailed Solution

Given r = 10, $δr = \pm 0. 02$

$V = \frac{4}{3} {πr}^{3}$

$\frac{δV}{V} × 100 = 3 \frac{δr}{r} × 100$

$δ V V \times 100 = 3 δ r r \times 100$

$= \pm 0. 6$

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