There is no S-S bond in

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There is no $S - S$ bond in

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$S_{2} O_{3}^{2 -}$

$S_{2} O_{7}^{2 -}$

$S_{4} O_{6}^{2 -}$

$S_{2} O_{4}^{2 -}$

answer is D.

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Detailed Solution

For $S_{2} O_{4}^{2 -}$ ,

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$For S_{4} O_{6} {}^{2 -},$

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$For S_{2} O_{3} {}^{2 -},$

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$For S_{2} O_{7} {}^{2 -},$

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$Thus, S_{2} O_{4} {}^{2 -}, S_{4} O_{6} {}^{2 -}{and} S_{2} O_{3} {}^{2 -}{has} S - S bond in it.$

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