Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

Thermal decomposition for $N_{2} O_{5 (g)}$ 1^storder kinetics as per $N_{2} O_{5 (g)} \to 2 {NO}_{2 (g)} +$ $\frac{1}{2} O_{2 (g)}$ Initial presure of $N_{2} O_{5}$ is 100mm. After 10 minutes, the pressure developed is 130mm, what is rate constant?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

a

0.693 min^–1

b

0.025 min^–1

c

$2.303 \times 10^{- 2}$ min^-1

d

0.03 min^–1

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\overset{t = 100 mm}{N_{2} O_{5}} \to 2 N O_{2} + \frac{1}{2} O_{2} t = 10 m i n 100 - x 2 x \frac{x}{2}$

at t= 10 mins

$100 - x + 2 x + \frac{x}{2} = 130$

x = 20

$K_{1} = \frac{2.303}{10} \log \frac{100}{100 - 20} = 0.2303 (1 - 0.9010) = 0.02303 \min^{- 1}$

Watch 3-min video & get full concept clarity

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!

Thermal decomposition for N2O5(g) 1st order kinetics as per N2O5(g)→2NO2(g)+12O2(g) Initial presure of N2O5 is 100mm. After 10 minutes, the pressure developed is 130mm, what is rate constant?