Thermal decomposition for $N_{2} O_{5 (g)}$ follows $1^{st}$ order kinetics as per $N_{2} O_{5 (g)} \to 2 {NO}_{2 (g)} +$ $\frac{1}{2} O_{2 (g)}$ . Initial pressure of $N_{2} O_{5}$ is $100 mm$ . After 10 minutes, the pressure developed is $80 mm$ , what is rate constant?

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$2.303 \times 10^{- 4} \min^{- 1}$

$0.693 \min^{- 1}$

$0.025 \min^{- 1}$

$0.03 \min^{- 1}$

answer is B.

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Detailed Solution

$\ln \frac{P_{o}}{P_{t}} = Kt \ln \frac{100}{80} = K \times 10 0.223 = K \times 10 K = 2.23 \times 10^{- 2}$

Therefore, the correct option is (B).

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