Thermal decomposition for N2O5( g) follows 1st order kinetics as per N2O5( g)→2NO2( g)+12O2( g). Initial pressure of N2O5 is 100 mm. After 10 minutes, the pressure developed is 80 mm, what is rate constant?

lnPoPt=Kt ln10080=K×10 0.223=K×10 K=2.23×10-2Therefore, the correct option is (B).

Thermal decomposition for N2O5( g) follows 1st order kinetics as per N2O5( g)→2NO2( g)+12O2( g). Initial pressure of N2O5 is 100 mm. After 10 minutes, the pressure developed is 80 mm, what is rate constant?

lnPoPt=Kt ln10080=K×10 0.223=K×10 K=2.23×10-2Therefore, the correct option is (B).

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Thermal decomposition for $N_{2} O_{5 (g)}$ follows $1^{st}$ order kinetics as per $N_{2} O_{5 (g)} \to 2 {NO}_{2 (g)} +$ $\frac{1}{2} O_{2 (g)}$ . Initial pressure of $N_{2} O_{5}$ is $100 mm$ . After 10 minutes, the pressure developed is $80 mm$ , what is rate constant?

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$2.303 \times 10^{- 4} \min^{- 1}$

$0.693 \min^{- 1}$

$0.025 \min^{- 1}$

$0.03 \min^{- 1}$

answer is B.

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$\ln \frac{P_{o}}{P_{t}} = Kt \ln \frac{100}{80} = K \times 10 0.223 = K \times 10 K = 2.23 \times 10^{- 2}$

Therefore, the correct option is (B).

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Thermal decomposition for N2O5( g) follows 1st order kinetics as per N2O5( g)→2NO2( g)+12O2( g). Initial pressure of N2O5 is 100 mm. After 10 minutes, the pressure developed is 80 mm, what is rate constant?

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Thermal decomposition for $N_{2} O_{5 (g)}$ follows $1^{st}$ order kinetics as per $N_{2} O_{5 (g)} \to 2 {NO}_{2 (g)} +$ $\frac{1}{2} O_{2 (g)}$ . Initial pressure of $N_{2} O_{5}$ is $100 mm$ . After 10 minutes, the pressure developed is $80 mm$ , what is rate constant?