Thermal decomposition of a $M n$ compound (X) at 513 K results in compound Y, $M n O_{2}$ and a gaseous product. $M n O_{2}$ reacts with $N a C l$ and concentrated $H_{2} S O_{4}$ to give a pungent gas Z, X, Y and Z respectively are

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$K_{3} {MnO}_{4}, {KMnO}_{4} and {Cl}_{2}$

$K_{3} {MnO}_{4}, K_{2} {MnO}_{4} and {Cl}_{2}$

$K_{2} {MnO}_{4}, {KMnO}_{4} and {SO}_{2}$

${KMnO}_{4}, K_{2} {MnO}_{4} and {Cl}_{2}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Thermal decomposition of $Mn$ compound (X), i.e. ${KMnO}_{4}$ at 513K produces compound Y (i.e. $K_{2} {MnO}_{4}$ ), ${MnO}_{2}$ , and a gaseous product.
${MnO}_{2}$ reacts with $NaCl$ and concentrated $H_{2} {SO}_{4}$ to form the pungent gas Z (i.e. $C l_{2}$ ).
The following are the reactions:

$2 K \underset{(X)}{M} {nO}_{4} \underset{Δ}{\overset{513 K}{⟶}} K_{2} \underset{(Y)}{M} {nO}_{4} + {MnO}_{2} + O_{2} (g)$

${MnO}_{2} + 4 NaCl + 4 H_{2} {SO}_{4} \to {MnCl}_{2} + 4 {NaHSO}_{4} + 2 H_{2} O + \underset{pungent gas}{{Cl}_{2 (g} (Z)}$

Watch 3-min video & get full concept clarity