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Q.

Thickness of a paper = 0.03 mm. Thickness of paper in standard form is:


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a

3× 10 −4  mm  

b

3× 10 −5  mm  

c

3× 10 −7  mm  

d

3× 10 −2  mm   

answer is D.

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Detailed Solution

Given thickness of a paper = 0.03 mm.
According to the question, simplifying to normal form,
=0.03 = 3 100  
= 3 10 2  
Now, using property of exponents
a b n =a× b −n  
=3× 10 −2   Thickness of paper in standard form is 3× 10 −2   mm.
Hence, option 4 is correct.
 
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