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Thiosulphate reacts differently with iodine and bromine in the reactions given below
$\begin{array}{l} 2 S_{2} {O_{3}}^{2 -} + I_{2} \to S_{4} {O_{6}}^{2 -} + 2 I^{-} \\ S_{2} {O_{3}}^{2 -} + 2 {Br}_{2} + 5 H_{2} O \to 2 {SO}_{4}^{2 -} + 2 {Br}^{-} + 10 H^{+} \end{array}$
Which of the following statements in correct ?

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a

Bromine is a stronger oxidant than iodine

b

Bromine is a weaker oxidant than iodine

c

Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions

d

Bromine undergoes oxidation and iodine undergoes reduction in these reactions

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detailed solution

Correct option is A

Iodine oxidizes $S_{2} O_{3}^{2 -}$ to $S_{4} O_{6}^{2 -}$ in which, S has low oxidation state +2.5, but bromine oxidizes $S_{2} O_{3}^{2 -}$ to ${SO}_{4}^{2 -}$ in which, sulphur has higher oxidation state +6. So, Bromine oxidizes more and therefore, it is stronger oxidizng agent than iodine.

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