Thiosulphate reacts differently with iodine and bromine in the reactions given below
$\begin{array}{l} 2 S_{2} {O_{3}}^{2 -} + I_{2} \to S_{4} {O_{6}}^{2 -} + 2 I^{-} \\ S_{2} {O_{3}}^{2 -} + 2 {Br}_{2} + 5 H_{2} O \to 2 {SO}_{4}^{2 -} + 2 {Br}^{-} + 10 H^{+} \end{array}$
Which of the following statements in correct ?

Question

Infinity Learn · Accepted Answer

Iodine oxidizes $$S2O32-$$​ to $$S4O62-$$​ in which, S has low oxidation state $$+2.5$$, but bromine oxidizes $$S2O32-$$​ to $$SO42-$$​ in which, sulphur has higher oxidation state $$+6$$. So, Bromine oxidizes more and therefore, it is stronger oxidizng agent than iodine.

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Thiosulphate reacts differently with iodine and bromine in the reactions given below2S2O32−+I2→S4O62−+2I−S2O32−+2Br2+5H2O→2SO42−+2Br−+10H+Which of the following statements in correct ?

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