Thiosulphate reacts differently with iodine and bromine in the reactions given below
$\begin{array}{l}2{\mathrm{S}}_2{{\mathrm{O}}_3}^{2-}+{\mathrm{I}}_2\to {\mathrm{S}}_4{{\mathrm{O}}_6}^{2-}+2{\mathrm{I}}^{-}\\ {\mathrm{S}}_2{{\mathrm{O}}_3}^{2-}+2{\mathrm{Br}}_2+5{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{SO}}_4^{2-}+2{\mathrm{Br}}^{-}+10{\mathrm{H}}^{+}\end{array}$
Which of the following statements in correct ?

Iodine oxidizes ${\mathrm{S}}_2{\mathrm{O}}_3^{2-}$​ to ${\mathrm{S}}_4{\mathrm{O}}_6^{2-}$​ in which, S has low oxidation state +2.5, but bromine oxidizes ${\mathrm{S}}_2{\mathrm{O}}_3^{2-}$​ to ${\mathrm{SO}}_4^{2-}$​ in which, sulphur has higher oxidation state +6. So, Bromine oxidizes more and therefore, it is stronger oxidizng agent than iodine.