Three equal charges$2\times {10}^{-6}\text{C}$  each, are held fixed at three corners of equilateral triangle of side 5 cm. The coulombic force experienced by one of the charge due to the rest two

$\text{F}=2\text{F}\cos \left(\text{60/2}\right)$                            $\text{F}=\frac{1}{4\pi {\epsilon }_0}\frac{{\text{q}}^{\text{2}}}{{\text{r}}^{\text{2}}}$

$=2\text{F}\cos 30$                                        $=9\times {10}^9\times \frac{4\times {10}^{-12}}{25\times {10}^{-4}}$

$=2\text{F}\times \frac{\sqrt{3}}{2}$                                          $=\frac{36}{25}\times {10}^1$

$=\sqrt{3}\text{F}$                                             $=1.44\times 10$ $=14.4$

$=\sqrt{3}\times 14.4=24.94\text{N}$