Three alternating voltage sources V1=3sinωt volt, V2=5sinωt+ϕ1 volt and V3=5sinωt−ϕ2 volt connected across a resistance R=73Ω as shown in the figure (whereϕ1 and ϕ2 corresponds to 30∘ and 127∘ respectively). Find the peak current (in amp.) through the resistor.

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Three alternating voltage sources $V_{1} = 3 \sin ω t$ volt, $V_{2} = 5 \sin (ω t + ϕ_{1})$ volt and $V_{3} = 5 \sin (ωt - ϕ_{2})$ volt connected across a resistance $R = \sqrt{\frac{7}{3}} Ω$ as shown in the figure (where $ϕ_{1}$ and $ϕ_{2}$ corresponds to $30^{\circ}$ and $127^{\circ}$ respectively). Find the peak current (in amp.) through the resistor.

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answer is 3.

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