Three batteries having Emf  $E_1=12V,E_2=14V$ and  $E_3=2V$ and internal resistance $R_1=4\Omega ,R_2=8\Omega$ and  $R_3=12\Omega$ are connected with each other as shown in Figure. Then, 

The internal resistance of the combination across A and B is  $\frac{24}{11}\Omega$

The equivalent Emf across A and B is 10Volt

The internal resistance of the combination across A and B is  $\frac{34}{11}\Omega$

The equivalent Emf across A and B is 20 Volt