Three blocks a, b, and c of masses 10 kg, 10 kg and 20 kg are arranged as shown in figure. All the surfaces are frictionless and string is inextensible. Pulleys are light. A constant force F = 20 N is applied on block a as shown. Pulleys and string are light. Part of the string connecting both pulleys is vertical and part of the strings connecting pulleys with blocks a and b are horizontal.

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Acceleration of mass blocks a, b and c is 0.5 m/s².

Acceleration of mass block b is 1.

Tension in the string is 10 N.

Acceleration of mass block c is 0.5

answer is B, C.

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Detailed Solution

$F - T = 10 \times a \dots (1) \begin{array}{ll} T = 10 \times a \dots (2) \\ F = 20 a \Rightarrow a = 1 \\ T = 10 N, a_{a} = a_{b} = 1, a_{c} = 0 \end{array}$

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