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Three blocks $A, B, C$ of mass 1 kg, 2 kg and 3 kg are placed on smooth horizontal surface as shown. Coefficient of friction between A, B and C is 0.40. A force F is applied on block A. Force is applied in such a way that system moves together with maximum possible acceleration $(g = 10 m / s^{2})$
Column – I Column – II
(A) Force F is (P) 2.4 N
(B) Friction force between A and B is (Q) 4.0 N
(C) Friction force between B and C is (R) 4.8 N
(D) Net force on A is (S) 0.8 N
(T) 1.6 N

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$A \to (Q); B \to (S); C \to (P); D \to (R)$

$A \to (R); B \to (Q); C \to (P); D \to (S)$

$A \to (Q); B \to (R); C \to (P); D \to (S)$

$A \to (R); B \to (Q); C \to (S); D \to (P)$

answer is D.

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Detailed Solution

$a = \frac{F}{6} 4 = 5 a a = 0.8 m / s^{2} F = 4.8 N$

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