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Three blocks are connected as shown in figure on a horizontal frictionless table. If $m_{1} = 1 kg,$ $m_{2} = 8 kg, m_{3} = 27 kg and T_{3} = 36 N,$
$T_{2} will be$

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18 N

9 N

3.375 N

1.75 N

answer is B.

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Detailed Solution

$T_{3} = (m_{1} m_{2} + m_{3}) a$

$\Rightarrow 36 = (1 + 8 + 27) a \Rightarrow a = 1 m / s^{2}$

Now $T_{2} = (m_{1} + m_{2}) a = (1 + 8) \times 1 = 9 N$

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