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Q.

Three blocks are placed as shown in figure below. The mass of A, B and C are m₁, m₂ and m_3, respectively. The force exerted by block C on B is

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a

$(m_{1} + m_{2}) g$

b

$m_{2} g$

c

$m_{1} g$

d

$(m_{1} + m_{2} + m_{3}) g$

answer is B.

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Detailed Solution

detailed_solution_thumbnail

As the system of blocks are in equilibrium.

The force exerted by block C on B must balance the weight of A and B.

So, ${F = m}_{1} {g+m}_{2} g= (m_{1} {+m}_{2}) g$

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