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Q.

Three blocks of masses 5 kg, 3 kg and 2 kg  are placed on rough surface (μk=0.1) as shown in figure. A horizontal force of 20 N is applied on 5 kg block. The force exerted by 3 kg block on 2 kg  block is (in Newton):

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answer is 4.

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Detailed Solution

If a is the acceleration of the blocks, then

20-μN=10a

or 20-0.1×10g=10a

∴a=1 m/s2

Now F1-f=2a

or F1-0.1×2g=2×1

∴F1=4 N

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