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Three blocks of masses $m_{1} = 10 kg, m_{2} = 20 kg$ and $m_{3} = 30 kg$ are on a smooth horizontal table, connected to each other by light horizontal strings. A horizontal force F=60 N is applied to 5 $m_{3}$ , towards right. Find tension in the string between and $T_{2}$ .

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30 N

40 N

50 N

60 N

answer is A.

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Detailed Solution

$T_{1} = 10 a, T_{2} - T_{1} = 20 a, 60 - T_{2} = 30 a$

$a = \frac{Net pulling force}{Total mass} = \frac{60}{10 + 20 + 30} = 1$ $m / s^{2}$

On solving, we get $T = 10 N, T_{2} = 30 N$ .

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