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Q.

Three blocks S, R and P connected by string are arranged as shown in the figure. The masses of S, R and P are 5 kg, 5 kg and 10 kg respectively. The tension in the string connecting R and P is (ignore friction)

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a

20 N

b

30 N

c

25 N

d

10 N

answer is B.

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Detailed Solution

mpg−T=mpa….(1)

T+mRg−T1=mRa…. (2) 

T=msa

a=mR+mPgmP+mR+mS

=5g+10g20=15×1020=7.5m/s2

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mpg−T=mpa

100 - T = 10(7.5)
T = 100 - 75
= 25N

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