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Q.

Three bodies each of mass m are placed at three corners of a square of side a.  The gravitational force on unit mass kept at fourth corner is

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a

Gm3a2

b

Gm3a2

c

3Gma2

d

Gma2(2+12)

answer is D.

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Detailed Solution

F1=F2=Gma2,F3=Gm2a2 Fnet=F12+F22+F3 =2Gma2+Gm2a2 =Gma2(2+12)

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