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Q.

Three capacitors are connected to D.C. source of 100 volt. If the charge accumulated on plates of a, b, c, d, e and f are $q_{a}, q_{b}, q_{c}, q_{d}, q_{e} a n d q_{f}$ respectively, then

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a

$q_{b} + q_{d} + q_{f} = 0$

b

$q_{b} + q_{d} + q_{f} = \frac{100}{9} C$

c

$q_{b} = q_{d} = q_{f}$

d

$q_{a} + q_{c} + q_{e} = 50 C$

answer is D.

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Detailed Solution

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All three capacitors have same charge. Plates b, d and f have positive charge.

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