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Q.

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

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a

$\frac{C}{3}, 3 V$

b

$3 C, \frac{v}{3}$

c

$\frac{C}{3}, \frac{V}{3}$

d

$3 C, 3 V$

answer is B.

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Detailed Solution

In series combination of capacitors

$\begin{array}{l} V_{eff} = V + V + V = 3 V \\ \frac{1}{c_{eff}} = \frac{1}{c} + \frac{1}{c} + \frac{1}{c} \\ so C_{eff} = \frac{C}{3} \end{array}$

Thus, the capacitance and breakdown voltage of the combination will be $\frac{C}{3} and 3 V$

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Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be