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Q.

Three capacitors of capacitance 3µF are connected in a circuit. Then their maximum and minimum capacitances will be

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a

9µF,0µF

b

3µF,2µF

c

8µF,2µF

d

9µF,1µF

answer is A.

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Detailed Solution

$C_{p} = 3 C = 3 \times 3 \times 10^{- 6} = 9 μF C_{max} = 9 μF; C_{s} = \frac{C}{3} = \frac{3}{3} = 1 μF; C_{min} = 1 μF$

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Three capacitors of capacitance 3µF are connected in a circuit. Then their maximum and minimum capacitances will be