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Three capacitors of capacitance $6 μ F$ are connected in a circuit. Then their maximum and minimum capacitances will be

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$18 μ F, 2 μ F$

$3 μ F, 2 μ F$

$9 μ F, 0 μ F$

$8 μ F, 2 μ F$

answer is A.

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Detailed Solution

Capacitance will be maximum when they are connected in parallel combination

$C_{P} = 3 \times 6 = 18 μ F$

Capacitance will be minimum when they are connected in series combination

$C_{S} = \frac{6}{3} μ F = 2 μ F$

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