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Q.

Three capacitors of capacitances 1μF,2μF  and  3μFare connected to a battery of negligible internal resistance as shown in the figure. The ratio of the charges on 2μF  and  3 μF capacitors is
 

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a

1 : 1

b

1 : 2

c

2 : 3

d

1 : 4

answer is C.

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Detailed Solution

Ceq=(1+2)×3(1+2)+3=32μF

q3 μF=Ceq×V=3V2μC

q2μF=2(1+2)×3V2=V μC

q2 μFq3 μF=23

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