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Q.

Three capacitors of capacitances, 2 pF, 3 pF and 4 pF are connected in parallel.

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a

If 3pF is shorted effective capacity is 2pF.

b

The total capacitance of combination is equal to $\frac{12}{13} pF$ .

c

Total capacitance is equal to 9 pF.

d

The total charge is equal 900 pC when connected to 100 V supply.

answer is B, C.

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Detailed Solution

$\begin{array}{l} V = 100 \\ q = C V \end{array}$
So $2 \times 10^{- 12} \times 100 = Q_{1}$
$\begin{array}{l} 3 \times 10^{- 12} \times 100 = Q_{2} \\ 4 \times 10^{- 12} \times 100 = Q_{3} \end{array}$
Total charge $Q_{1} + Q_{2} + Q_{3}$
$900 \times 10^{- 12} = 900 p C$
C-effective $= C_{1} + C_{2} + C_{3}$
$2 + 3 + 4 = 9 p F$

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