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Three charges +q, -q and -q are kept at the vertices of an equilateral triangle of 10cm side. The potential at the mid point in between -q, -q, if q = 5µC is

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$- 6.4 \times 10^{5} V$

$- 12.8 \times 10^{4} V$

$- 6.4 \times 10^{4} V$

$- 12.8 \times 10^{5} V$

answer is D.

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Detailed Solution

$\begin{array}{l} V = V_{1} + V_{2} + V_{3}; V_{1} = V_{2} = \frac{1}{4 {πε}_{0}} \frac{(- q)}{(a / 2)} \\ V_{3} = \frac{1}{4 {πε}_{0}} \frac{(q)}{(\frac{\sqrt{3} a}{2})} \end{array}$

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