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Three charges Q, +q and +q are placed at the vertices of a right angled isosceles triangle as shown in Fig. The net electrostatic energy of configuration is zero, if Q is equal to:

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$\frac{- q}{1 + \sqrt{2}}$

$\frac{- 2 q}{2 + \sqrt{2}}$

$- 2 q$

answer is B.

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Detailed Solution

$U = u_{1} + u_{2} + u_{3}$

$u = k [\frac{Qq}{a} + \frac{q^{2}}{a} - \frac{Qq}{\sqrt{2 a}}] = 0$

$Q = \frac{- 2 q}{2 + \sqrt{2}}$

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