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Three charges +Q , q, +Q are placed respectively , at distance 0 , $\frac{d}{2}$ and d from the origin , on the x-axis. If the net force experienced by +Q , placed at x=0 , is zero, then value of q is

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$+ \frac{Q}{4}$

$- \frac{Q}{2}$

$+ \frac{Q}{2}$

$- \frac{Q}{4}$

answer is D.

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Detailed Solution

$\frac{Q Q}{d^{2}} + \frac{Q q}{{(d / 2)}^{2}} = 0$

$Q + 4 q = 0$

$q = \frac{- Q}{4}$

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